Q. Determine the amount of heat to be taken out a price of hot iron block of mass 300gm to cool it from 300 C to 20 C? Specific heat of iron = 480 J/kgC

Soln:

Mass of iron (m) = 300gm = 0.3kg

Sp. Heat Capacity (S) = 480 J/Kg⁰C

Change in temperature (dt) = 300 -20 = 280⁰C

Quantity of heat (Q) = ?

Using the formula,

Q = m*S*dt = 0.3*480*280 = 40320 J Ans.