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Home Comp. Mathematics Prove that: angle AXD = 1/2 (arc AD - arc Bc)

Sunday, January 7, 2018

Prove that: angle AXD = 1/2 (arc AD - arc Bc)

Soln:

Join AC then
angle AXD + angle CAX = angle ACD [External property of a triangle]
angle AXD + (1/2) arc BC = (1/2) arc AD [The relation between arc and incribed angle]
angle AXD = (1/2) (arc AD - arc BC) [Taking arc BC to the R.H.S.]