Q. Prove that : tan20 + 4sin20 = root 3
S.E.E. Solution
5.0
stars based on
35
reviews
Soln: L.H.S. = tan20 + 4sin20 = sin20/cos20 + 4sin20 = (sin20 + 4sin20.cos20)/(cos20) = (sin20 + 2sin40)/cos20 = [sin20 + 2sin...
SUBSCRIBE TO OUR NEWSLETTER
Q. Evaluate: Cos6° × sin24° × cos72°
Soln:
Cos6° × sin24° × cos72°
= (1/2) * 2 Cos6° × sin24° × cos72°
= (1/2) [sin(6+24) – sin(6-24)] * cos72
= (1/2) ... Prove that: (sin3Acos2A-cos3ASin2A)/(cos3Acos2A+sin3Asin2A) = TanA
L.H.S
=(sin3Acos2A-cos3ASin2A)/(cos3Acos2A+sin3Asin2A)
=(sin(3A-2A))/(cos(3A-2A)
=sinA/cosA
=tanA
... Prove that: [tan(alpha)+sec(alpha)-1]/[tan(alpha)-sec(alpha)+1] = [1+sin(alpha)]/cos(alpha)
Soln
... Q. 8cos^3(20) - 8sin^3(10) - 6cos20 + 6sin10 = 2
Soln:
L.H.S.
= 8cos320 – 8sin310 – 6cos20 + 6sin10
= 2(4cos320 – 4sinn310 – 3cos20 +
3sin10)
= 2(4cos320 - 3cos20 + 3sin10
... Prove that: sin6.sin42.sin66.sin78 = 1/16
Soln:
... A complete solution for SEE students.
