Soln:
L.H.S.
= [1 + Tan2(p/4-A)]/[1 – Tan2(p/4-A)]
= 1/[{1 – Tan2(p/4-A)}/{ 1 + Tan2(p/4-A)}]
= 1/[cos2(p/4-A)] [Since, cos2A = (1 – Tan2A)/(1 + Tan2A)]
= 1/[cos(p/2-2A)]
= 1/sin2A
= cosec2A = R.H.S
Q.Prove that: [1+Tan^2(pie/4-A)] / [1-Tan^2(pie/4-A)] = cosec2A
![Q.Prove that: [1+Tan^2(pie/4-A)] / [1-Tan^2(pie/4-A)] = cosec2A](https://blogger.googleusercontent.com/img/b/R29vZ2xl/AVvXsEinGiOEaD5LPLqioiclipXvWEh8E5qSkBGwjNqIAtw0LjlC5ZpiCgwAGGCj53_TiIRRs6-n_Uq_8iH-vDjhMt9xytukA2QzZaedzC0_hwpVoO2qe45Cn6Dmm0oIYOz_dkS5aA-ee6BnzIim/s72-c/coollogo_com-4440765.png)
Q.Prove that: [1+Tan^2(pie/4-A)] / [1-Tan^2(pie/4-A)] = cosec2A
S.E.E. Solution
5.0
stars based on
35
reviews
Soln: L.H.S. = [1 + Tan 2 ( p /4-A)]/[1 – Tan 2 ( p /4-A)] = 1/[{1 – Tan 2 ( p /4-A)}/{ 1 + Tan 2 ( p /4-A)}] = 1/[cos2( p /4-A)...
SUBSCRIBE TO OUR NEWSLETTER
You May Also Like
- Q. The sum of first four terms in a G.P. is 30 and that of the last four terms is 960.if its first term is 2 and last term is 512, find the common ratio.
Soln:
Let first term = a and last term = b of GP.
According to the given condition, the sum of first four terms is 30 i.e.
...
- From the top of the tower on the sea shore anjan observes a boat coming to the shore at angle of depression of 30 degree after 10 min he finds the angle of depression 60 degree what time will take the boat to reach the bottom of the tower on shore from the starting point?
Soln:
...
- Prove that: sin6.sin42.sin66.sin78 = 1/16
Soln:
...
- Prove that: [tan(alpha)+sec(alpha)-1]/[tan(alpha)-sec(alpha)+1] = [1+sin(alpha)]/cos(alpha)
Soln
...
- 11. Find the number of geometric means inserted between 1 and 243 in which the ratio of the first mean to the last mean is 1:27.
Soln:
...
