Soln:
Mass of iron (m) = 300gm = 0.3kg
Sp. Heat Capacity (S) = 480 J/Kg0C
Change in temperature (dt) = 300 -20 = 2800C
Quantity of heat (Q) = ?
Using the formula,
Q = m*S*dt = 0.3*480*280 = 40320 J Ans.
Q. Determine the amount of heat to be taken out a price of hot iron block of mass 300gm to cool it from 300 C to 20 C? Specific heat of iron = 480 J/kgC
Q. Determine the amount of heat to be taken out a price of hot iron block of mass 300gm to cool it from 300 C to 20 C? Specific heat of iron = 480 J/kgC
S.E.E. Solution
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Soln: Mass of iron (m) = 300gm = 0.3kg Sp. Heat Capacity (S) = 480 J/Kg 0 C Change in temperature (dt) = 300 -20 = 280 0 C Quant...
