Wednesday, July 5, 2017

Q. Find the point which divides the line joining the points (1,-2) and (3,2) in the ratio 1:3.


Soln:

Note: If internal division or external division is not mentioned in question, by default, the problem should be solved by using Section Formula for internal division. 
We have,
(x1,y1) = (1,-2) 
(x2,y2) = (3,2) 
m:n = 1:3 
When we put these information in the formula, we get the required point .
Require point   = [(mx2+nx1)/(m+n), (my2+ny1)/(m+n)]
Required point = [(1X3 +3x1)/(1+3), (1X2+3x-2)/(1+3)] 
                           = [(3+3)/4, (2-6)/4] 
                           = (3/2, -1) 
Hence the required point is (3/2, -1) Ans.