=(sin3Acos2A-cos3ASin2A)/(cos3Acos2A+sin3Asin2A)
=(sin(3A-2A))/(cos(3A-2A)
=sinA/cosA
=tanA
Prove that: (sin3Acos2A-cos3ASin2A)/(cos3Acos2A+sin3Asin2A) = TanA
=(sin3Acos2A-cos3ASin2A)/(cos3Acos2A+sin3Asin2A)
=(sin(3A-2A))/(cos(3A-2A)
=sinA/cosA
=tanA
Prove that: (sin3Acos2A-cos3ASin2A)/(cos3Acos2A+sin3Asin2A) = TanA
S.E.E. Solution
5.0
stars based on
35
reviews
L.H.S =(sin3Acos2A-cos3ASin2A)/(cos3Acos2A+sin3Asin2A) =(sin(3A-2A))/(cos(3A-2A) =sinA/cosA =tanA
SUBSCRIBE TO OUR NEWSLETTER
You May Also Like
- Q. Evaluate: Cos6° × sin24° × cos72°
Soln:
Cos6° × sin24° × cos72°
= (1/2) * 2 Cos6° × sin24° × cos72°
= (1/2) [sin(6+24) – sin(6-24)] * cos72
= (1/2) ...
- Prove that: sin6.sin42.sin66.sin78 = 1/16
Soln:
...
- Q. Use remainder theorem to find remainder when polynomial x^6-1 is divided by x+1.
Soln:
Remainder Theorem:
Statement: “When polynomial
f(x) is divided x-a then remainder is f(a).”
Here, f(x) = x^6-1
Comparing ...
- Prove that: (2cosA + 1)(2cosA - 1)(2cos2A - 1) = 2cos4A + 1
Soln:
...
- Prove that: [tan(alpha)+sec(alpha)-1]/[tan(alpha)-sec(alpha)+1] = [1+sin(alpha)]/cos(alpha)
Soln
...
