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Prove that: [tan(alpha)+sec(alpha)-1]/[tan(alpha)-sec(alpha)+1] = [1+sin(alpha)]/cos(alpha)
Tuesday, February 6, 2018
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Soln: L.H.S. = cosec40 - Ö 3sec40 = 1/sin40 - Ö 3/cos40 = 1/sin40 - tan60/cos40 [tan60= Ö 3] = 1/sin40 - sin60/(cos40.cos6...
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Soln: Use formula: cos2A = 2cos^2(A) - 1 cos2A+1= 2cos^2(A) (1+cos2A)/2 = cos^2(A) i.e. cos^2(A) = (1+cos2A)/2
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