Sunday, July 9, 2017

Q. 8cos^3(20) - 8sin^3(10) - 6cos20 + 6sin10 = 2

Soln:

L.H.S.
= 8cos320 – 8sin310 – 6cos20 + 6sin10
= 2(4cos320 – 4sinn310 – 3cos20 + 3sin10)
= 2(4cos320 - 3cos20 + 3sin10 – 4sin310)
= 2(cos3.20 + sin3.10)   [ cos3A = 4cos3A – 3cosA and sin3A = 3sinA – 4sin3A]
= 2(cos60 + sin30)
= 2(1/2 + 1/2)
= 2