Q. Is BA compatible ? If so compute BA, if not give reason.

SUBSCRIBE TO OUR NEWSLETTER
You May Also Like
Prove that: (2cosA + 1)(2cosA - 1)(2cos2A - 1) = 2cos4A + 1 Soln: ...
Q. 8cos^3(20) - 8sin^3(10) - 6cos20 + 6sin10 = 2 Soln: L.H.S. = 8cos320 – 8sin310 – 6cos20 + 6sin10 = 2(4cos320 – 4sinn310 – 3cos20 + 3sin10) = 2(4cos320 - 3cos20 + 3sin10 ...
Q. Prove that: 4(cos^4A+sin^4A)/(cos^4A-sin^4A)=(3+cos4A)Sec2A ...
Q. Prove that: (cos5a.sin2a-cos4a.sin3a)/(sin5a.sin2a-cos4a.cos3a) = cot2a Soln: L.H.S. = (cos5a.sin2a-cos4a.sin3a)/(sin5a.sin2a-cos4a.cos3a) Multiply numerator and denominator by 2. = 2(cos5a.sin2a - ...
Q. Evaluate: Cos6° × sin24° × cos72° Soln: Cos6° × sin24° × cos72° = (1/2) * 2 Cos6° × sin24° × cos72° = (1/2) [sin(6+24) – sin(6-24)] * cos72 = (1/2) ...